2k^2+13k=0

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Solution for 2k^2+13k=0 equation: 



2k^2+13k=0

a = 2; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·2·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*2}=\frac{-26}{4}
=-6+1/2
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*2}=\frac{0}{4}
=0
$

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